Comments on: How to list numeric file permissions on Linux

By: artemus

artemus — Thu, 04 Aug 2011 21:27:59 +0000

Any way to make the above do this recursively from, say, the current directory?

Thanks,

Scott

By: Florin

Florin — Tue, 20 Oct 2009 11:25:02 +0000

Great! I was looking for a command to list permission in octal, of a file. Now i found it. Thanks Garry.

By: Titusz

Titusz — Thu, 02 Apr 2009 21:42:28 +0000

thanks Garry… that makes it much easier…

By: Garry

Garry — Thu, 02 Apr 2009 18:17:36 +0000

While I’m at it, there’s a handy alias that will display the “human readable” permissions, the numeric permissions, the size in bytes (padded to 8 characters), and time of last modification (truncated at 19 characters), and the filename, including any provided path spec:

alias d=’stat -c “%A (%a) %8s %.19y %n” ‘

You would use the command thus:

d Src/*

-rw-r–r– (644) 3808 2009-03-27 17:12:34 Src/DaemonClient.cpp
-rw-r–r– (644) 8898 2009-04-02 10:29:23 Src/DaemonObject.cpp
-rw-r–r– (644) 4782 2009-03-31 11:39:12 Src/main.cpp

Hope someone finds that useful.

By: Garry

Garry — Thu, 02 Apr 2009 17:56:59 +0000

You can use stat directly.

stat -c “%a %n” *

will output the octal file permissions and file name of all files in the current directory.

stat -c “%a %n” /home/mydir/source/*

will do the same for all files in /home/mydir/source/ (if you leave off the “/*” at the end, stat will just tell you that it’s a directory).